In the lab you react 2.0 g of Na2CO3 with enough CaCl2. According to the reaction Na2CO3 + CaCl2 - > CaCO3 + 2NaCl How much CaCO3 will you produce?

1.89 g CaCO₃

Explanation:

You will have to use stoichiometry for this question. First, look at the chemical equation.

Na₂CO₃ + CaCl₂ = => 2 NaCl + CaCO₃

From the above equation, you can see that for one mole of Na₂CO₃, you will produce one mole of CaCO₃. This means that however many moles of Na₂CO₃ you have in the beginning, you will have the same amount of moles of CaCO₃, theoretically speaking.

So, convert grams to moles. You should get 0.0189 mol Na₂CO₃. This means that you will get 0.0189 mol CaCO₃. I'm not sure what units you want the answer in, but I'm going to give it in grams. Convert moles to grams. Your answer should be 1.89 g.