Ask Question
4 April, 01:20

Be sure to answer all parts. a buffer is prepared by mixing 50.0 ml of 0.050 m sodium bicarbonate, nahco3, and 10.7 ml of 0.10 m naoh. (ka = 4.7 * 10-11) what is the ph?

+3
Answers (1)
  1. 4 April, 01:47
    0
    Moles HCO3 - = 0.0500L*0.050M = 0.0025

    Moles OH - added = 0.0107L*0.10M = 0.00107

    Moles CO32 - forms = 0.00107

    Moles HCO3 - in excess = 0.0025-0.00107=0.00143

    Total volume = 10.7 + 50.0 = 60.7mL = 0.0607L

    [HCO3-] = 0.00143 / 0.607 = 0.0236M

    [CO32-] = 0.00107/0.0607 = 0.0176M

    pKa = 10.3

    PH = 10.3 + log 0.0176/0.0236 = 10.2.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Be sure to answer all parts. a buffer is prepared by mixing 50.0 ml of 0.050 m sodium bicarbonate, nahco3, and 10.7 ml of 0.10 m naoh. (ka ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers