4. You have a very concentrated solution (12 M) of potassium chloride (KCI). You need it to be at the least concentration possible for the experiment you are

about to conduct. The problem is you forgot to order lab supplies, so you only have 2 L of distilled water left. What would be the final concentration if you

added the two 2 L of distilled water to the 0.5 L of 12 M KCI?

a 3.0 M

b 24 M

C 2.4M

d 48 M

Question

Ocean

Chemistry

3 October, 00:02

4. You have a very concentrated solution (12 M) of potassium chloride (KCI). You need it to be at the least concentration possible for the experiment you are

about to conduct. The problem is you forgot to order lab supplies, so you only have 2 L of distilled water left. What would be the final concentration if you

added the two 2 L of distilled water to the 0.5 L of 12 M KCI?

a 3.0 M

b 24 M

C 2.4M

d 48 M

+3

Answers (1)

Know the Answer?

Alyssa Holloway · Answer 1

C. 2.4 M

Explanation:

Because you started with 12M solution of KCl, that means that there was a concentration of 12 mols of KCl per Liter of solution. (12mol/1L = 12 M). Since there was only 0.5L of solution, there was only 6 mols of KCl because there is only 12 mols per 1 Liter, so half of that volume would have half the amount of solute to keep that true. (6mol/.5L = 12 M). With the new water added, the formula becomes (6mols KCl / 2.5L of water = 2.4 M)