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16 July, 14:20

If 35.2 g of hydrochloric acid react with excess of magnesium, how many grams of hydrogen are produced?

Mg + 2HCl - -> MgCl2 + H2

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  1. 16 July, 14:37
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    0.975 g of H₂

    Explanation:

    The equation for the reaction between magnesium and HCl is given by;

    Mg + 2HCl - -> MgCl2 + H2

    We are given 35.2 g of of HCl reacted with excess magnesium.

    We are required to calculate the amount of Hydrogen produced;

    Step 1: Calculation of number of moles of HCl

    To calculate the number of moles we divide the mass by the molar mass

    Molar mass of HCl = 36.46 g/mol

    Mass of HCl = 35.2 g

    Number of moles = 35.2 g : 36.46 g/mol

    = 0.965 moles

    Step 2: Moles of Hydrogen produced

    From the equation, the mole ratio of HCl to H₂ is 2 : 1

    Therefore; Moles of Hydrogen = Moles of HCl : 2

    = 0.965 moles : 2

    = 0.4825 moles

    Step 3: Mass of hydrogen gas produced

    Mass is calculated by multiplying the number of moles by the molar mass.

    Molar mass of hydrogen = 2.02 g/mol

    Moles of hydrogen = 0.4825 moles

    Mass of Hydrogen = 0.4825 moles * 2.02 g/mol

    = 0.97465

    = 0.975 g

    Therefore; 0.975 g of hydrogen will be produced.
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