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4 October, 05:30

8) what is the empirical formula for ethyl fluoride if the compound contains 49.97% carbon, 10.51% hydrogen, and 39.52% fluorine by mass?

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  1. 4 October, 05:39
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    43.97/12.01=3.661=2

    10.51/1.01=10.406=5

    39.52/19.00=2.075=1

    C2H5F
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