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21 February, 22:27

How many grams of Br are in 335g of CaBr2

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  1. 21 February, 22:36
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    The answer is 267.93 g

    Molar mass of CaBr2 is the sum of atomic masses of Ca and Br:

    Mr (CaBr2) = Ar (Ca) + 2Ar (Br)

    Ar (Ca) = 40 g/mol

    Ar (Br) = 79.9 g/mol

    Mr (CaBr2) = 40 + 2 * 79.9 = 199.8 g/mol

    The percentage of Br in CaBr2 is:

    2Ar (Br) / Mr (CaBr2) * 100 = 2 * 79.9 / 199.8 * 100 = 79.98%

    Now make a proportion:

    x g in 79.98%

    335 g in 100%

    x : 79.98% = 335 g : 100%

    x = 79.98% * 335 g : 100%

    x = 267.93 g
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