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Noel Lara
Chemistry
21 February, 22:27
How many grams of Br are in 335g of CaBr2
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Heaven Howard
21 February, 22:36
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The answer is 267.93 g
Molar mass of CaBr2 is the sum of atomic masses of Ca and Br:
Mr (CaBr2) = Ar (Ca) + 2Ar (Br)
Ar (Ca) = 40 g/mol
Ar (Br) = 79.9 g/mol
Mr (CaBr2) = 40 + 2 * 79.9 = 199.8 g/mol
The percentage of Br in CaBr2 is:
2Ar (Br) / Mr (CaBr2) * 100 = 2 * 79.9 / 199.8 * 100 = 79.98%
Now make a proportion:
x g in 79.98%
335 g in 100%
x : 79.98% = 335 g : 100%
x = 79.98% * 335 g : 100%
x = 267.93 g
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