How many grams of CO are needed to react with an excess of Fe2O3 to produce (210.3 g Fe) 209.7 g Fe? Show your work.

CO (g) + Fe2O3 (s) - - > Fe (s) + CO2 (g)

The balanced chemical reaction is given as:

3CO (g) + Fe2O3 (s) - - > 2Fe (s) + 3CO2 (g)

We are given the amount of the product to be produced from the reaction. We use this as the starting value for the calculations. We do as follows:

209.7 g Fe (1 mol / 210.3 g Fe) (3 mol CO / 2 mol Fe) (28.01 g / 1 mol) = 41.90 g CO needed