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27 April, 13:19

A stock solution of potassium permanganate (KMnO4) was prepared by dissolving 11.3 g KMnO4 with DI H2O in a 100.00-mL volumetric flask and diluting to the calibration mark. Determine the molarity of the solution.

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  1. 27 April, 13:22
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    [KMnO₄] = 0.71 M

    Explanation:

    Solute: Potassium permanganate, molar mass 158.04 g/mol

    Solvent: Water, volume of 100 mL

    We convert the mass of solute to moles:

    11.3 g. 1mol / 158.04g = 0.071 moles

    We asume the solvent's volume as the solution's volume

    We convert the volume from mL to L → 100 mL. 1L / 1000 mL = 0.1L

    Molarity (mol/L) → moles of solute in 1L of solution

    Molarity → 0.071 moles / 0.1 L = 0.71M
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