How many moles of a gas sample are in a 10.0 L container at 298 K and 203 kPa? (Use the ideal gas law PV = nRT with R = 8.31 L-kPa/mol-K).

Ideal gas law: PV = nRT

P-pressure

V-volume

n-number of moles (m/M)

R-constant

T - temperature

State given info:

V=10L

T=298k

P=203kPa

R=8.31 (only for kPa, for pressure at atm use 0.08206)

Sub in:

(203kPa) (10L) = n (8.31) (298)

Rearrange:

n = (203) (10) / (8.31) (298)

n = 0.819745mol in gas sample