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6 July, 23:21

If 30g of HCl is reacted with excess NaOH, and 10g of NaCl is produced, what is the percent yield of the experiment?

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  1. 6 July, 23:28
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    Percent yield = 20.85%

    Explanation:

    Given dа ta:

    Mass of HCl = 30 g

    Mass of NaCl produced = 10 g

    Percent yield of NaCl = ?

    Solution:

    Chemical equation:

    HCl + NaOH → NaCl + H₂O

    Number of moles of HCl:

    Number of moles = mass / molar mass

    Number of moles = 30 g / 36.5 g/mol

    Number of moles = 0.82 mol

    Now we will compare the moles of HCl with NaCl

    HCl : NaCl

    1 : 1

    0.82 : 0.82

    Theoretical yield:

    Mass of NaCl:

    Mass = number of moles * molar mass

    Mass = 0.82 mol * 58.5 g/mol

    Mass = 47.97 g

    Percent yield:

    Percent yield = Actual yield / theoretical yield * 100

    Percent yield = 10 g / 47.97 g * 100

    Percent yield = 20.85%
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