Silver nitrate solution reacts with calcium chloride solution according to the equation: 2 AgNO3 + CaCl2 → Ca (NO3) 2 + 2 AgCl All of the substances involved in this reaction are soluble in water except silver chloride, AgCl, which forms a solid (precipitate) at the bottom of the flask. Suppose we mix together a solution containing 6.97 g of AgNO3 and one containing 6.39 g of CaCl2. What mass, in grams, of AgCl is formed?

Question

Marble

Chemistry

17 March, 04:31

Silver nitrate solution reacts with calcium chloride solution according to the equation: 2 AgNO3 + CaCl2 → Ca (NO3) 2 + 2 AgCl All of the substances involved in this reaction are soluble in water except silver chloride, AgCl, which forms a solid (precipitate) at the bottom of the flask. Suppose we mix together a solution containing 6.97 g of AgNO3 and one containing 6.39 g of CaCl2. What mass, in grams, of AgCl is formed?

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Answers (1)

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Gilbert · Answer 1

14.33 g

Explanation:

Solve this problem based on the stoichiometry of the reaction.

To do that we need the molecular weight of the masses involved and then calculate the number of moles, find the limiting reagent and finally calculate the mass of AgCl.

2 AgNO₃ + CaCl₂ ⇒ Ca (NO₃) ₂ + 2 AgCl

mass, g 6.97 6.39?

MW, g/mol 169.87 110.98 143.32

mol = m/MW 0.10 0.06 0.10

From the table above AgNO₃ is the limiting reagent and we will produce 0.10 mol AgCl which is a mass:

0.10 mol x 143.32 g/mol = 14.33 g