What is the volume of a 0.120 M solution that contains 9.35 g of HCI?

2.13L

Explanation:

first you must find the amount (mols) of HCl in the solution. then you can use that to find the volume of the solution.

we know the:

mass m = 9.35g

molar mass M = 1 + 35.5=36.5 g/mol (check periodic table)

concentration c = 0.120 mol/L

amount (mols) of HCl:

n = m/M

n (HCl) = 9.35/36.5

= 0.2561644 mol

concentration of HCl in solution:

n = cV

V (HCl) = n/c

= 0.2561644/0.120

= 2.1347

= 2.13 L (3sf)