A reaction between solid sulphur and oxygen produces sulfur dioxide. What is the percent yield for a reaction if you predicted the formation of 680g of sulfur dioxide and actually recovered only 384g?

56.47%

Explanation:

In this question, we are given;

Theoretical yield of sulfur dioxide as 680 g Actual yield of sulfur dioxide as 384 g

We are required to calculate the percent yield for the reaction;

We need to know how percent yield is calculated; % yield = (Actual yield : Theoretical yield) * 100%

Therefore;

In this case;

% yield = (384 g : 680 g) * 100%

= 56.47%

Thus, the percent yield for the reaction is 56.47%