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24 November, 12:54

2 Al + 3 Cl2 = 2 AlCl3

114g Al

186g Cl2

to use all of the Al how much Cl2 is required

+2
Answers (2)
  1. 24 November, 13:04
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    ur mom
  2. 24 November, 13:08
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    1 mol Al. 26.9815 g Al. *. 2 mol AlCl. 3. 2 mol Al. = 0.100 mol AlCl3. The balanced equation says: 3 mol Cl2 produces ... that the initial mass of Al was larger than required to react with all of the Cl2. The sum of the masses.

    Explanation:1 mol Al. 26.9815 g Al. *. 2 mol AlCl. 3. 2 mol Al. = 0.100 mol AlCl3. The balanced equation says: 3 mol Cl2 produces ... that the initial mass of Al was larger than required to react with all of the Cl2. The sum of the masses.
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