Determine how many grams of N2 are produced from the reaction of 8.37 g of H2O2 and 5.29 g of N2H4.

N₂H₄ + 2H₂O₂ → N₂ + 4H₂O

mol = mass : molar mass

If mass of hydrazine (N₂H₄) = 5.29 g

then mol of hydrazine = 5.29 g : ((14 * 2) + (1 * 4))

= 0.165 mol

mole ratio of hydrazine to Nitogen is 1 : 1

∴ if moles of hydrazine = 0.165 mol

then moles of nitrogen = 0.165 mol

Mass = mol * molar mass

Since mol of nitrogen (N₂) = 0.165

then mass of hydrazine = 0.165 * (14 * 2)

= 4.62 g