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13 October, 17:11

What is the mole fraction of glucose when 46.2 g glucose C 6H 12O 6 (molar mass 180.2 g/mol) is dissolved in 65.1 g water?

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Answers (2)
  1. 13 October, 17:13
    0
    The mol fration of glucose is 0.0662

    Explanation:

    Step 1: Data given

    Mass glucose = 46.2 grams

    Molar mass glucose = 180.2 g/mol

    Mass water = 65.1 grams

    Molar mass water = 18.02 g/mol

    Step 2: Calculate moles glucose

    Moles glucose = mass glucose / molar mass glucose

    Moles 46.2 grams / 180.2 g/mol

    Moles glucose = 0.256 moles

    Step 3: Calculate moles H2O

    Moles H2O = 65.1 grams / 18.02 g/mol

    Moles H2O = 3.61 moles

    Step 4: Calculate mol fraction glucose

    Mol fraction glucose = 0.256 moles / (0.256+3.61) moles

    Mol fraction glucose = 0.0662

    The mol fration of glucose is 0.0662
  2. 13 October, 17:30
    0
    Answer:0.2564

    Explanation:

    this because when you divide whatis given by the molarmass of glucose we would get the answer above
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