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14 March, 18:08

Find the initial temperature of Aluminum if 35 g of it produces 781.2 Joules at the final temperature of 44.3 ºC.

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  1. 14 March, 18:11
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    T initial = 19.55°C

    Explanation:

    Given dа ta:

    Mass of Al = 35 g

    Energy produces = 781.2 J

    Final temperature = 44.3°C

    Initial temperature = ?

    Solution:

    Specific heat capacity:

    It is the amount of heat required to raise the temperature of one gram of substance by one degree.

    Specific heat capacity of Al is 0.902 J/g.°C

    Formula:

    Q = m. c. ΔT

    Q = amount of heat absorbed or released

    m = mass of given substance

    c = specific heat capacity of substance

    ΔT = change in temperature

    ΔT = Final temperature - initial temperature

    Q = m. c. ΔT

    781.2 J = 35 g*0.902 J/g.°C * (T final - T initial)

    781.2 J = 35 g*0.902 J/g.°C * (44.3°C - T initial)

    781.2 J = 31.57 j/°C * (44.3°C - T initial)

    781.2 J / 31.57 j/°C = (44.3°C - T initial)

    24.75°C = (44.3°C - T initial)

    24.75° - 44.3°C = - T initial

    T initial = 19.55°C
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