The stock solution of hydrochloric acid is 12.0M HCI. If the teacher starts with 130 ml of this concentrated acid, what volume of 3.0M HCI can be prepared?

520mL

Explanation:

Data obtained from the question include:

Molarity of stock solution (M1) = 12M

Volume of stock solution (V1) = 130mL

Molarity of diluted solution (M2) = 3M

Volume of diluted (V2) = ... ?

The volume of the diluted solution can be obtained as follow:

M1V1 = M2V2

12 x 130 = 3 x V2

Divide both side by 3

V2 = 12 x 130 / 3

V2 = 520mL.

Therefore, 520mL of the diluted solution can be prepared.