Find the number of bromine molecules present in 2.25 mol.

Question

Savanna Griffin

Chemistry

3 April, 03:30

Find the number of bromine molecules present in 2.25 mol.

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Snoop · Answer 1

Answer is: the number of bromine molecules is 1.35·10²⁴.

n (Br₂) = 2.25 mol; amount of bromine molecules.

Na = 6.022·10²³ mol⁻¹; Avogadro constant.

N (Br₂) = n (Br₂) · Na.

N (Br₂) = 2.25 mol · 6.022·10²³ mol⁻¹.

N (Br₂) = 13.54 ·10²³.

N (Br₂) = 1.35·10²⁴; number of bromine molecules.