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11 October, 22:27

The natural abundances of elements in the human body, expressed as percent by mass, are oxygen (o), 65 percent; carbon (c), 18 percent; hydrogen (h), 10. Percent; nitrogen (n), 3.0 percent; calcium (ca), 1.6 percent; phosphorus (p), 1.2 percent; all other elements, 1.2 percent. Enter your answers in scientific notation. Calculate the mass in grams of each element in the body of a 64-kg person.

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  1. 11 October, 22:40
    0
    O: 4.2 * 10⁴ g

    C: 1.2 * 10⁴ g

    H: 6.4 * 10³ g

    N: 1.9 * 10³ g

    Ca: 1.0 * 10³ g

    P: 7.7 * 10² g

    Other elements: 7.7 * 10² g

    Explanation:

    Natural abundances of elements in the human body (in percent by mass)

    oxygen (O), 65% carbon (C), 18% hydrogen (H), 10% nitrogen (N), 3.0% calcium (Ca), 1.6% phosphorus (P), 1.2% all other elements, 1.2%

    The mass of a body is 64 kg = 64 * 10³ g = 6.4 * 10⁴ g. We can calculate the mass of each element by multiplying the body weight by the mass percent of each element.

    O: 6.4 * 10⁴ g * 65% = 4.2 * 10⁴ g

    C: 6.4 * 10⁴ g * 18% = 1.2 * 10⁴ g

    H: 6.4 * 10⁴ g * 10% = 6.4 * 10³ g

    N: 6.4 * 10⁴ g * 3.0% = 1.9 * 10³ g

    Ca: 6.4 * 10⁴ g * 1.6% = 1.0 * 10³ g

    P: 6.4 * 10⁴ g * 1.2% = 7.7 * 10² g

    Other elements: 6.4 * 10⁴ g * 1.2% = 7.7 * 10² g
  2. 11 October, 22:49
    0
    It is given that the person weighs 62 kg = 62,000 g

    Natural abundances in mass percent are:

    O = 65%

    C = 18%

    H = 10%

    N = 3.0%

    Ca = 1.6%

    P = 1.2%

    Corresponding weights of the elements are:

    O = 65/100 * 62000 g = 40.30 * 10^3 g

    C = 18/100 * 62000 g = 11.16 * 10^3 g

    H = 10/100 * 62000 g = 62.00 * 10^2 g

    N = 3.0/100 * 62000 g = 18.60 * 10^2 g

    Ca = 1.6/100 * 62000 g = 9.92 * 10^2 g

    P = 1.2/100 * 62000 g = 7.44 * 10^2 g
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