3Pb2 + (aq) + 2Cr (s) → 3Pb (s) + 2Cr3 + (aq) What is the number of moles of electrons gained by 3.0 moles of lead ions?

Question

Olivia Payne

Chemistry

11 August, 20:01

3Pb2 + (aq) + 2Cr (s) → 3Pb (s) + 2Cr3 + (aq) What is the number of moles of electrons gained by 3.0 moles of lead ions?

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Esperanza Kelley · Answer 1

To determine the electrons gained in this redox reaction, we must balance the charges on the side containing the reduced substance and the side with oxidized substance. In this case, the reduced substance is Pb2 + and the oxidized substance is Cr. In each side, 6 electrons are gained or lose to balance the charges. The answer is 6 electrons.