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31 January, 06:33

A container holds 35.8 moles of gas under 10.0 atm of pressure at 70.0 C. What is the volume of the container? 20.6 L 101 L 2080 L 10200 L

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  1. 31 January, 06:36
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    PV = n RT

    P: pressure = 10atm

    V volume

    n number of mole = 35.8 moles

    R universal gas constant = 0.082

    T: The temperature = 70°C = 343.15 Kelvin

    V = (n RT) / P = 35.8 x 0.082 x 343.15 / 10 = 100.7 ≈ 101 L

    V = 101L
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