Nitrogen and hydrogen combine at a high temperature, in the presence of a catalyst, to produce ammonia. N2 (g) + 3H2 (g) ⟶2NH3 (g) Assume 0.100 mol N2 and 0.330 mol H2 are present initially. After complete reaction, how many moles of ammonia are produced?

The number of moles of ammonia produced are 0.2 moles.

Explanation:

Given dа ta:

Moles of N₂ = 0.100 mol

Moles of H₂ = 0.330 mol

Moles of NH₃ = ?

Solution:

First of all we will write the balance chemical equation

N₂ + 3H₂ → 2NH₃

Now we compare the moles of ammonia with nitrogen and hydrogen gas from balance chemical equation.

N₂ : NH₃

1 : 2

0.100 : 2/1 * 0.100 = 0.2 mol

H₂ : NH₃

3 : 2

0.330 : 2/3 * 0.330 = 0.22 mol

The number of moles of ammonia produced by nitrogen gas are less so nitrogen will be limiting reactant and number of moles of ammonia produced are 0.2 moles.