You have 627 ml of 5.04 M HCl. Using a volumetric pipet, you take 229 ml of that solution and dilute it to 921 ml in a volumetric flask. Now you take 100.00 ml of that solution and dilute it to 192 ml in a volumetric flask. What is the concentration of hydrochloric acid in the final solution? Enter your answer numerically in units of M to three significant figures.

Question

Aleena

Chemistry

4 February, 17:11

You have 627 ml of 5.04 M HCl. Using a volumetric pipet, you take 229 ml of that solution and dilute it to 921 ml in a volumetric flask. Now you take 100.00 ml of that solution and dilute it to 192 ml in a volumetric flask. What is the concentration of hydrochloric acid in the final solution? Enter your answer numerically in units of M to three significant figures.

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Answers (1)

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Ivy Sullivan · Answer 1

0.653

Explanation:

1)

M1V1 = M2V2

M1 = 5.04 M

V1 = 229 mL (you take only this volume)

V2 = 921 mL

5.04*229 = M2 * 921

M2 = (5.04*229) / 921 Molarity

2)

M1V1 = M2V2

M1 = (5.04*229) / 921

V1 = 100 mL

V2 = 192 mL

(5.04*229) / 921 * 100 = M2 * 192

M2 = [ (5.04*229) / 921 * 100]/192 = 0.653 final molarity