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6 February, 16:54

How many seconds are required to produce 4.00 g of aluminum metal from the electrolysis of molten alcl3 with an electrical current of 12.0 a? a. 1.19 ' 103 b. 27.0 c. 2.90 ' 105 d. 9.00 e. 3.57 ' 103?

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  1. 6 February, 17:10
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    The correct answer is e. 3.57*10³

    Al³ + (aq) + 3e→AL (s)

    4.00g of AL=4g/26.98 g/mol = 0.1483 mol

    t=znF/1 where t is time in seceonds.

    Z = valency number of ions of the substance or electrons which are transferred per ion

    F = Faraday's constant

    I = electric current in'A'CA C/s

    t = (3*0.1483 mol * 96485 C/mol) / 12 (C15)

    t=3577 second = 3.5 * 10³s
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