Ask Question
23 May, 04:56

At a certain temperature, the equilibrium constant, kc, for this reaction is 53.3. h2 (g) + i2 (g) â½âââ2hi (g) kc=53.3 at this temperature, 0.700 mol of h2 and 0.700 mol of i2 were placed in a 1.00-l container to react. what concentration of hi is present at equilibrium?

+2
Answers (1)
  1. 23 May, 05:07
    0
    5.11 mol/L.

    Explanation:

    For the reaction:

    H₂ (g) + I₂ (g) ⇄ 2HI (g), Kc = 53.3.

    ∵ Kc = [HI]²/[H₂][I₂]

    [H₂] = 0.70 mol/1.0 L = 0.70 mol/L.

    [I₂] = 0.70 mol/1.0 L = 0.70 mol/L.

    ∵ Kc = [HI]²/[H₂][I₂]

    ∴ [HI]² = Kc[H₂][I₂] = (53.3) (0.70) (0.70) = 26.117.

    ∴ [HI] = √26.117 = 5.11 mol/L.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “At a certain temperature, the equilibrium constant, kc, for this reaction is 53.3. h2 (g) + i2 (g) â½âââ2hi (g) kc=53.3 at this ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers