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24 April, 00:02

Consider the reaction mg (oh) 2 (s) →mgo (s) + h2o (l) with enthalpy of reaction δhrxn∘=37.5kj/mol what is the enthalpy of formation of mgo (s) ?

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  1. 24 April, 00:20
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    Answer is: - 601,2 kJ/mol

    Chemical reaction: Mg (OH) ₂ → MgO + H₂O.

    ΔHrxn = 37,5 kJ/mol.

    ΔHf (Mg (OH) ₂) = - 924,5 kJ/mol.

    ΔHf (H₂O) = - 285,8 kJ/mol.

    ΔHrxn - enthalpy of reaction.

    ΔHf - enthalpy of formation.

    ΔHrxn=∑productsΔHf-∑reactantsΔHf.

    ΔHf (MgO) = - 924,5 kJ/mol - (-285,8 kJ/mol) + 37,5 kj/mol.

    ΔHf (MgO) = - 601,2 kJ/mol.
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