The amount of sodium chloride in the original mixture can be determined indirectly by subtracting the masses of ammonium chloride and sand from the initial sample mass of 10.000 g. when you perform this calculation, what is the mass of the sodium chloride?

a. 6.527 g

b. 0.950 g

c. 14.250 g

d. 2.620 g submit for grading save and finish later

Question

Madisen

Chemistry

26 February, 03:26

The amount of sodium chloride in the original mixture can be determined indirectly by subtracting the masses of ammonium chloride and sand from the initial sample mass of 10.000 g. when you perform this calculation, what is the mass of the sodium chloride?

a. 6.527 g

b. 0.950 g

c. 14.250 g

d. 2.620 g submit for grading save and finish later

+2

Answers (1)

Know the Answer?

Jeremy Reynolds · Answer 1

Missing question:

mass of ammonium chloride (NH₄Cl) + mass of sand (SiO₂) = 1.222 g + 6.158 g = 7.38 g

m (initial sample) = 10,000 g.

m (sodium chloride-NaCl) = m (sample) - (m (NH ₄Cl) + m (SiO₂)) =

= 10 g - 7,38 g = 2,62 g.

Answer is: d. 2.620 g.