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30 November, 11:01

What is the ph of the solution prepared by dissolving 0.927 mol hcl in enough water to make a 150 l aqueous solution?

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  1. 30 November, 11:14
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    The answer to your question is pH = 2.2

    Explanation:

    Data

    pH = ?

    moles of HCl = 0.927

    volume = 150 l

    Process

    1. - Calculate the Molar concentration of HCl

    Molarity = moles / volume (L)

    Molarity = 0.927 / 150

    = 0.00618

    2. - Calculate the pH

    pH = - log [HCl]

    Substitution

    pH = - log [0.00618]

    Result

    pH = 2.2
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