The complete ionic equation for the reaction of aqueous sodium hydroxide with aqueous nitric acid is

Answer and Explanation:

Sodium hydroxide (NaOH) is a strong base and nitric acid (HNO₃) is a strong acid. That means that they dissociates in water by giving the ions:

NaOH ⇒ Na⁺ (ac) + OH⁻ (ac)

HNO₃ ⇒ H⁺ (ac) + NO₃⁻ (ac)

The reaction between an acid and a base is called neutralization. In this case, HNO₃ loses its proton and it is converted in NO₃⁻ (nitrate anion). NaOH loses its hydroxyl anion (OH⁻) by giving Na⁺ cations.

Na⁺ cations with NO₃⁻ anions form the salt NaNO₃ (sodium nitrate); whereas H⁺ and OH⁻ form water molecules. The complete equation is the following:

HNO₃ (ac) + NaOH (ac) ⇒ NaNO₃ (ac) + H₂O (l)

The ionic equation is:

H⁺ (ac) + NO₃⁻ (ac) + Na⁺ (ac) + OH⁻ (ac) ⇄ Na⁺ (ac) + NO₃⁻ (ac) + H₂O (ac)

If we cancel the repeated ions at both sides of the equation, it gives the following ionic reaction:

H⁺ (ac) + OH⁻ (ac) ⇄ H₂O (ac)