According to the balanced chemical equation, how many atoms of silver will be produced from combining 100 g of copper with 200 g of silver nitrate?

The balance chemical equation is as follow,

Cu + 2 AgNO₃ → Cu (NO₃) ₂ + 2 Ag

First calculate for 200 g of AgNO₃,

According to equation,

339.74 g (2 mole) AgNO₃ produced = 215.7 g (2 mole) of Ag

So,

200 g of AgNO₃ will produce = X g of Ag

Solving for X,

X = (200 g * 215.7 g) : 339.74 g

X = 126.97 g Ag

Next calculate for 100 g of Cu,

According to equation,

63.52 g (1 mole) Cu produced = 215.7 g (2 mole) of Ag

So,

100 g of Cu will produce = X g of Ag

Solving for X,

X = (100 g * 215.7 g) : 63.52 g

X = 339.57 g Ag

Result:

As 200 g of AgNO₃ is producing Ag in less amount (126.97 g) as compared to 100 g of Cu, it means that AgNO₃ is in limited amount and will consume first till the production of 126.97 g of Ag. So, the maximum amount of Ag production is 126.97 g.