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20 January, 23:38

What is the maximum number of moles of Al2O3 that can be produced by the reaction of. 4 mol of Al with. 4 mol of O2

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Answers (2)
  1. 20 January, 23:48
    0
    Given:

    Moles of Al = 0.4

    Moles of O2 = 0.4

    To determine:

    Moles of Al2O3 produced

    Explanation:

    4Al + 3O2 → 2Al2O3

    Based on the reaction stoichiometry:

    4 moles of Al produces 2 moles of Al2O3

    Therefore, 0.4 moles of Al will produce:

    0.4 moles Al * 2 moles Al2O3/4 moles Al = 0.2 moles Al2O3

    Similarly;

    3 moles O2 produces 2 moles Al2O3

    0.4 moles of O2 will yield: 0.4 * 2/3 = 0.267 moles

    Thus Al will be the limiting reactant.

    Ans: Maximum moles of Al2O3 = 0.2 moles
  2. 20 January, 23:52
    0
    There can 0.2 moles Al2O3 be produced

    Explanation:

    Step 1: Data given

    Moles of Al = 0.4 moles

    Moles of O2 = 0.4 moles

    Step 2: The balanced equation

    4Al + 3O2 → 2Al2O3

    Step 3: Calculate the limiting reactant

    For 4 moles Al we need 3 moles O2 to produce 2 moles Al2O3

    Al is the limiting reactant. It will completely be consumed. (0.4 moles).

    O2 is in excess. Therer ill react 3/4*0.4 = 0.3 moles O2

    There will remain 0.4 - 0.3 = 0.1 mol

    Step 4: Calculate moles of Al2O3

    For 4 moles Al we need 3 moles O2 to produce 2 moles Al2O3

    For 0.4 moles Al we'll have 0.4/2 = 0.2 moles Al2O3

    There can 0.2 moles Al2O3 be produced
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