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3 February, 01:38

Solid lithium and iodine gas are formed by the decomposition of solid lithium iodide.

Write a balanced chemical equation for this reaction.

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  1. 3 February, 02:00
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    Lithium Iodide is

    LiI

    Lithium has a charge of 1+, and Iodide has a charge of 1-, thus this is the correct form.

    Remember Iodine is Diatomic when it is alone! So I_2

    LiI (s) - > Li (s) + I_2 (g)

    Is the formula you get when you simply write it out, but now we need to balance it.

    1 Lithium, 1 Iodide - > 1 Lithium + 2 Iodine

    We need 2 Iodine on the left side, so we can add coefficients to the left to create that balance.

    2 (1 Lithium, 1 Iodide) - > 1 Lithium + 2 Iodine

    is the same as ...

    2LiI - > Li + I_2

    Now we have to balance the Lithiums on the right ... so our final balanced equation is:

    2LiI - > 2Li + I_2

    (Note that the _2 is a subscript of 2)
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