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23 September, 05:43

If 2.76 g of CuNO3 is dissolved in water to make a 0.350 M solution, what is the volume of the solution?

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  1. 23 September, 06:08
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    I can't remember any of the weights of the individual elements but here is how you solve it:

    Molecular weight of copper + nitrogen + 3 oxygens = molecular weight of the compound.

    M = moles / liter

    .350 moles / 1 liter

    Do. 350 moles / liter x the molecular weight (g / mole) of the compound = the answer in g / L
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