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Consider the chemical reaction 2NH3 (g) N2 (g) + 3H2 (g). The equilibrium is to be established in a 1.0-L container at 1000 K, where Kc = 4.0 * 10-2. Initially, 1.22 moles of NH3 (g) are present. What is the equilibrium concentration of H2 (g) ?

Question

Londyn

Chemistry

6 March, 05:33

How do I do this?

Consider the chemical reaction 2NH3 (g) N2 (g) + 3H2 (g). The equilibrium is to be established in a 1.0-L container at 1000 K, where Kc = 4.0 * 10-2. Initially, 1.22 moles of NH3 (g) are present. What is the equilibrium concentration of H2 (g) ?

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Answers (1)

Know the Answer?

Grant Gill · Answer 1

The chemical reaction is as follows:

2NH3 (g) = N2 (g) + 3H2 (g)

We do the ice method to answer this.

NH3 N2 H2

I 1.22 0 0

C - 2x x 3x

E 1.22 - 2x x 3x

Kc = [h2]^3 [n2] / [nh3]^2

4.0 * 10^-2 = 27x^3 (x) / (1.22 - 2x) ^2

x = 0.259 mol

H2 = 0.259/1 = 0.259 mol/L

How do I do this?Consider the chemical reaction 2NH3 (g) N2 (g) + 3H2 (g). The equilibrium is to be established in a 1.0-L container at 1000 K, where Kc = 4.0 * 10-2. Initially, 1.22 moles of NH3 (g) are present. What is the equilibrium concentration of H2 (g) ?

How do I do this?

Consider the chemical reaction 2NH3 (g) N2 (g) + 3H2 (g). The equilibrium is to be established in a 1.0-L container at 1000 K, where Kc = 4.0 * 10-2. Initially, 1.22 moles of NH3 (g) are present. What is the equilibrium concentration of H2 (g) ?