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9 October, 04:57

A bag filled with lead shots is dropped from a height of h = 38.2 m. The total mass of the bag is m = 745.0 g. What is the increase in the temperature of the lead shots, after the bag hits the ground? The specific heat of lead is c = 130 J/kgK. Tries 0/99

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  1. 9 October, 05:06
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    The increase of temperature is 2.88 Kelvin

    Explanation:

    Step 1: Data given

    Height = 38.2 meter

    Total mass of the bag with lead m = 745.0 grams

    Specific heat of lead c = 130J/kg * K

    Step 2: Calculate change in temperature

    Q = heat transfer

    Q = m*c*ΔT

    with m = mass

    with c = specific heat capacity

    with ΔT = change in temperature

    Q = Potential energy

    Potential energy = m*g*h

    with m = mass

    with g = acceleration due to gravity (9.81 m/s²)

    with h = height

    m*g*h = m*c*ΔT

    ΔT = (m*g*h) / m*c

    ΔT = g*h/c

    ΔT = 9.81*38.2 / 130

    ΔT = 2.88 °C

    The increase of temperature is 2.88 Kelvin
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