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26 May, 12:32

A certain ore yields an average of 64 % iron. how much ore is needed to obtain 896 lb of iron?

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  1. 26 May, 12:33
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    In this case, the ore yield 64% iron and you need 896 lb of iron. From this description you can get an equation like this:

    Iron = iron ore mass * 64%

    Then, to get 896 of iron the calculation should be:

    Iron = iron ore mass * 64%

    896 lb = iron ore mass * 0.64

    iron ore mass = 896 lb / 0.64 = 1400lb
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