In a thermonuclear device, the pressure of 0.050 liters (V1) of gas within the bomb casing reaches a pressure of 4.0 x 106 atm (P1). When the bomb casing is destroyed by the explosion, the gas is released into the atmosphere where it reaches a pressure of 1.00 atm (P2). What is the volume (V2) of the gas after the explosion

Question

Shamar Mccullough

Chemistry

5 July, 01:53

In a thermonuclear device, the pressure of 0.050 liters (V1) of gas within the bomb casing reaches a pressure of 4.0 x 106 atm (P1). When the bomb casing is destroyed by the explosion, the gas is released into the atmosphere where it reaches a pressure of 1.00 atm (P2). What is the volume (V2) of the gas after the explosion

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Friday · Answer 1

See explanation below

Explanation:

In this case, we can assume that the temperature is the same in both conditions. Let's assume that the temperature is 25 °C.

If the temperature is constant we can use the Boyle's law to calculate the volume. This law is:

P₁V₁ = P₂V₂

You should note that this expression is only valid when you have a constant temperature.

Solving for V₂:

V₂ = P₁V₁ / P₂

So all we have to do is replace the given values:

V₂ = 0.05 * 4x10⁶ / 1

V₂ = 200,000 L