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26 July, 09:46

a 45g sample of water at 12°c is heated with 15kJ of energy. What will be the final temperature of the water?

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  1. 26 July, 10:08
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    Final temperature = 91.75 °C

    Explanation:

    Given dа ta:

    Mass of water = 45 g

    Initial temperature = 12 °C

    Energy required = 15 Kj (15000 j)

    Final temperature = ?

    Formula:

    Q = m. c. ΔT

    Q = amount of heat absorbed or released

    m = mass of given substance

    c = specific heat capacity of substance

    ΔT = change in temperature

    Solution:

    Q = m. c. ΔT

    15000 j = 45 g * 4.18 j/g.°C * (T2 - T1)

    15000 j = 45 g * 4.18 j/g.°C * (T2 - 12 °C)

    15000 j = 188.1 J/°C * (T2 - 12 °C)

    15000 j / 188.1 J/°C = T2 - 12 °C

    79.745 °C = T2 - 12 °C

    T2 = 79.745 °C + 12 °C

    T2 = 91.75 °C
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