Determine the molar solubility of fe (oh) 2 in pure water. ksp for fe (oh) 2 = 4.87 * 10-17

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Travis Gilmore

Chemistry

2 May, 23:44

Determine the molar solubility of fe (oh) 2 in pure water. ksp for fe (oh) 2 = 4.87 * 10-17

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Ignacio · Answer 1

Answer is: molar solubility of iron (II) hydroxide is 2,3·10⁻⁶ M.

Chemical reaction: Fe (OH) ₂ (s) → Fe²⁺ (aq) + 2OH⁻ (aq).

s (Fe (OH) ₂) = ? M.

s (Fe (OH) ₂) = s (Fe²⁺) = x.

s (OH⁻) = 2s (Fe (OH) ₂) = 2x.

Ksp = s (Fe²⁺) · (s (OH⁻)) ².

Ksp = x · (2x) ².

4,87·10⁻¹⁷ = 4x³.

x = ∛ (4,87·10⁻¹⁷ : 4).

x = 2,3·10⁻⁶ M.