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b. 1. eliseo couldn't find the 6 m hcl and so used 6 m hno3 for testing the metals instead. his logic? both are strong acids. explain how the results of the experiment would have been different.

If Eliseo used the 6 M HNO3 for the substitution for 6M HCI, thus the product would have yielded a blue solution, whereas there would actually no reaction had he used the 6 M HCI as instructed. Being a good oxidizing agent it oxidizes the compound itself whereas HCL takes part in the reaction and is very volatile, thus HNO3 should have not been used in redox titration.

We all know that HNO3 should have not been used in this redox titration because being an oxidizing agent it corrodes the compound itself while HCL is a very unstable or volatile and it takes slice in the response. And the final outcome would have produced a blue solution, whereas there would really be no reaction had he used the 6 M HCl as taught.