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3 October, 00:27

A gas system has an unknown pressure and an initial temperature of 299K. When the temperature is increased to 620 K the pressure is measured at 7.77 atm. The volume is constant throughout. What was the initial pressure in atm?

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  1. 3 October, 00:28
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    3.75 atm

    Explanation:

    Volume remains constant, so we can use Gay-Lussac's Law.

    p₁/T₁ = p₂/T₂ Multiply both sides by T₁

    p₁ = p₂ * T₁/T₂

    p₁ = ?; T₁ = 299 K

    p₂ = 7.77 atm; T₂ = 620 K Insert the values

    p₁ = 7.77 * 299/620 Do the operations

    p₁ = 3.75 atm
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