A 8.46 L sample oxygen gas at 267K and 1.23 atm is heated to 295K. If the volume changes to 6.98L, what is the new pressure?

The new pressure is 1,65 atm

Explanation:

We use the gas formula, which results from the combination of the Boyle, Charles and Gay-Lussac laws. According to which at a constant mass, temperature, pressure and volume vary, keeping constant PV / T.

(P1xV1) / T1 = (P2xV2) / T2

(1,23atmx 8,46L) / 267 K = (P2 x 6,98L) / 295K

0,039 atmx L/K = (P2 x 6,98L) / 295K

P2 = (0,039 atmx L/K) x 295K/6,98L = 1,65 atm