The volume of a gas is increased from 445mL to 515ml. If the initial pressure was 120kPa, what is the final pressure of the gas?

Answer: 103.7 kPa

Explanation:

Given that:

initial volume of gas V1 = 445ml

initial pressure of gas P1 = 120 kPa.

new Volume V2 = 515ml

new pressure P2 = ?

Since, only pressure and volume are involved, apply the formula for Boyle's law

P1V1 = P2V2

120 kPa x 445ml = P2 x 515 kPa

53400 = P2 x 515 kPa

P2 = 53400/515

P2 = 103.7 kPa

Thus, the final pressure of the gas is 103.7 kPa