Barium hydroxide dissolves as follows. ba (oh) 2 (s) ? ba2 + (aq) + 2oh - (aq) how many moles of ba (oh) 2 are required to make 1.0 l of solution in which the ohconcentration is 0.050 m?

Question

Todd

Chemistry

10 March, 11:51

Barium hydroxide dissolves as follows. ba (oh) 2 (s) ? ba2 + (aq) + 2oh - (aq) how many moles of ba (oh) 2 are required to make 1.0 l of solution in which the ohconcentration is 0.050 m?

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Mylie · Answer 1

There are a number of ways to express concentration of a solution. This includes molarity. Molarity is expressed as the number of moles of solute per volume of the solution. We calculate as follows:

0.050 M = 0.050 mol / L solution

Moles Ba (OH) 2 = 0.050 mol / L solution (1 L solution) = 0.050 mol Ba (OH) 2