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20 February, 02:10

If you have 2.63 grams of the organic fuel (MW=74.09 g / mol) and 5.63 grams of oxygen gas, how many grams of carbon dioxide will you produce?

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  1. 20 February, 02:21
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    Mass of CO₂ = 3.08 g

    Explanation:

    Given dа ta:

    Mass of organic fuel = 2.63 g

    Molar mass of organic fuel = 74.09 g/mol

    Mass of oxygen = 5.63 g

    Mass of carbon dioxide = ?

    Solution:

    Chemical equation:

    2C₃H₆O₂ + 7O₂ → 6CO₂ + 6H₂O

    Number of moles of organic fuel:

    Number of moles = mass / molar mass

    Number of moles = 2.63 g / 74.09 g/mol

    Number of moles = 0.035 mol

    Number of moles of oxygen:

    Number of moles = mass / molar mass

    Number of moles = 5.63 g / 32 g/mol

    Number of moles = 0.176 mol

    Now we will compare the moles of O₂ and C₃H₆O₂ with CO.

    C₃H₆O₂ : CO

    3 : 6

    0.035 : 6/3 * 0.035 = 0.07

    O₂ : CO

    7 : 6

    0.176 : 6/7 * 0.176 = 0.151 mol

    The number of moles of CO₂ produced by C₃H₆O₂ are less it will be limiting reactant.

    Mass of carbondioxide:

    Mass of CO₂ = moles * molar mass

    Mass of CO₂ = 0.07 mol * 44 g/mol

    Mass of CO₂ = 3.08 g
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