Consider the chemical formula for one unit of aluminum sulfate, Al2 (SO4) 3. How many total atoms would be present in 22 units of aluminum sulfate?

1.32*10²⁵ atoms of sulfate are contained in 22 units of it

Explanation:

1 unit = 1 mol

Al₂ (SO₄) ₃ → Aluminum sulfate

As 1 unit = 1 mol, 1 unit has 6.02*10²³ atoms of aluminum sulfate.

Let's make a rule of three:

1 unit of Al₂ (SO₄) ₃ contains 02*10²³ atoms

Then, 22 units of Al₂ (SO₄) ₃ must contain (22. 6.02*10²³) / 1 = 1.32*10²⁵ atoms