A chemist is working on a reaction represented by this chemical equation:

FeCl2 + 2KOH → Fe (OH) 2 + 2KCl.

If the chemist uses 4.15 moles of iron (II) chloride and 3.62 moles of potassium hydroxide, how many moles of iron (II) hydroxide will the reaction produce?

A. 1.81 mol

B. 3.62 mol

C. 4.15 mol

D. 7.24 mol

Question

Nylah Frost

Chemistry

3 August, 12:55

A chemist is working on a reaction represented by this chemical equation:

FeCl2 + 2KOH → Fe (OH) 2 + 2KCl.

If the chemist uses 4.15 moles of iron (II) chloride and 3.62 moles of potassium hydroxide, how many moles of iron (II) hydroxide will the reaction produce?

A. 1.81 mol

B. 3.62 mol

C. 4.15 mol

D. 7.24 mol

+4

Answers (2)

Know the Answer?

Jaelynn · Answer 1

Answer is: A. 1.81 mol.

Balanced chemical reaction: FeCl₂ + 2KOH → Fe (OH) ₂ + 2KCl.

n (FeCl₂) = 4.15 mol; amount of iron (II) chloride.

n (KOH) = 3.62 mol; amount of potassium hydroxide, limiting reactant.

From chemical reaction: n (KOH) : n (Fe (OH) ₂) = 2 : 1.

n (Fe (OH) ₂) = n (KOH) : 2.

n (Fe (OH) ₂) = 3.62 mol : 2.

n (Fe (OH) ₂) = 1.81 mol; amount of iron (II) hydroxide.

Lincoln Schultz · Answer 2

It's A. 1.81 mol. This answer is on Plato.

#PlatoLivesMatter