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25 September, 19:57

Nitrogen and hydrogen gases are combined at high temperatures and pressures to produce ammonia, NH3. If 101.7 g of N2 are reacted with excess H2, how many moles of NH3 will be formed

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  1. 25 September, 20:20
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    In this reaction, 7.26 moles of NH3 will be formed.

    Explanation:

    Step 1: Data given

    Mass of N2 = 101.7 grams

    Molar mass N2 = 28.0 g/mol

    H2 is in excess

    Molar mass H2 = 2.02 g/mol

    Molar mass of NH3 = 17.03 g/mol

    Step 2: The balanced equation

    N2 (g) + 3H2 (g) → 2NH3 (g)

    Step 3: Calculate moles N2

    Moles N2 = mass N2 / molar mass N2

    Moles N2 = 101.7 grams / 28.0 g/mol

    Moles N2 = 3.63 moles

    Step 4: Calculate moles NH3

    For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

    For 3.63 moles N2 we'll produce2*3.63 = 7.26 moles NH3

    In this reaction, 7.26 moles of NH3 will be formed.
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