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16 June, 18:06

White wines tend to be more acidic than red wines. Find the [H3O ] in a Sauvignon Blanc with a pH of 3.23 and a Cabernet Sauvignon with a pH of 3.64. How many times more acidic is the Sauvignon Blanc

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  1. 16 June, 18:17
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    The answers are:

    [H3O] Sauvignon Blanc = 0.000588

    [H3O] Cabernet Sauvignon = 0.000229

    Sauvignon Blanc is 2.57 times more acid than Cabernet Sauvignon

    Explanation:

    The pH is a measure to calculate the degree of alkalinity or acidity of a solution. Knowing the pH we can calculate the hydrogenation concentration of the two wines. We have to clear the equation:

    pH = - log [H3O]

    [H3O] = 10^-pH

    Replacing we have:

    [H3O] Sauvignon Blanc = 10^-3.23 = 0.000588

    [H3O] Cabernet Sauvignon = 10^-3.64 = 0.000229

    To calculate how many times the Sauvignon Blanc is more acidic than the Cabernet Sauvignon, we just have to divide both hydrogen concentrations, as follows:

    0.000588/0.000229 = 2.57 times more acid
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